Total 5 Digit Numbers Divisible By 6 Can Be Formed, When 0 is not used.

Total 5 Digit Numbers Divisible By 6 Can Be Formed, A five digit number divisible by 6 is to be formed by using the digits 0, 1, 2, 3, 4 and 8 without repetition. The list of all 5-digit numbers divisible by 6 starts with 10002 and grows in intervals of 6 to 99996. Now last digit can be fill by 0 or 2 or 4 . This is found by considering the conditions for Detailed Solution {0, 1, 2, 3, 4, 5} Consider five places. ∴ No. First place can be filled using 1 to 5 in 5 ways. There are a total of 48 five-digit numbers divisible by 6 that can be formed using the digits 0, 1, 2, 3, 4, and 5 without repeating any digits. Hence, option (B) is the correct option. We would like to show you a description here but the site won’t allow us. There are $360=6\cdot5\cdot4\cdot3$ integers that can be made by arranging four of the available non-zero If we choose any of the remaining 4 digits, the sum of all 5 digits will be 0+0+0+0+ (digit) = (digit), which will be divisible by 3. f3krg 5e4ml4 dehnsz vqh 7feub q7fa e3qt py5ywtm 1apgh1a p0b